User:Fanofkinopio

First, let c = cherry b = banana t = toast w = cupcake s = sundae p = pie (Note that these pronumerals denote ONE of the item (e.g. in line 3 there are three french toasts, thus this equals 3t)) Now set up simultaneous equations: $$ 3c=3$$ $$ (cb)+b=4 $$ $$ 3t+2c+3t=20 $$ $$ (w+c)^2+3t=45 $$ $$ {\frac{s}{2c}}+3b=11 $$ $$ 2p-(w+3c)=s+2c+3b $$ '''Using a calculator, solve all equations. This should give:'''
 * c = 1
 * s = 10
 * t = 3
 * w = -7 or 5
 * b = 2
 * p = 13

Now, for the final equation: $$ w+[(4t+3b)*(s+c)]-(p+b) $$ $$ =5+{[(4*3)+(3*2)]*(10*1)}-(13+2) $$ $$ =5+(18*11)-15 $$ Which gives you the answer of 188, when w = 5

Now, when w = -7: $$ w+[(4t+3b)*(s+c)]-(p+b) $$ $$ =-7+[[(4*3)+(3*2)]*(10*1)]-(13+2) $$ $$ =-7+(18*11)-15 $$ Which gives you the answer of 176, when w = -7