Board Thread:Support Requests - Getting Technical/@comment-30724837-20161213142754/@comment-30724837-20161213180324

I've looked at the suggestions, a good part of it before creating this thread as I looked for something on my own. Maybe I missed something but I don't see how I can, with a--single--string (no other input), get something which the following regex would do (\d\d)(\d\d)(\d\d) substituted for \3-\2-20\1.