Thread:ByAsura/@comment-25295648-20200806192204/@comment-25295648-20200816125749

Just to entertain it however:




 * MC80 width = 478 pixels = 260.608814175 meters
 * MC80 length = 2201 pixels = 1200 meters = 259.518401 meters



Ship Width = 220x50 pixels = 225.610283454 pixels = 260.608814175 meters

225.610283454/69.0796641567 = 3.26594354805

Beam Width = 64x26 pixels = 69.0796641567 pixels = 79.7958723 meters

(pi(39.89793615 meters)^2)*3.70149 kilometers = 18,510,890.6 cubic meters

18,510,890.6 cubic meters * 1023.6 kg/m^3 = 18,947,747,618.2 kilograms

Blasters are hot, can even vaporize starfighters. I will assume the boiling point of titanium (3287 degrees celsius)

Average temperature of seawater is is 17 degrees celsius, making a temperature change of 3269 degrees

https://www.omnicalculator.com/physics/specific-heat

= 58.61898056444678 megatons of tnt

Latent heat is 540 calories per gram

540 calories per gram * 18,947,747,618.2 kilograms = 10.2317837 megatons of tnt

10.2317837 megatons of tnt + 58.61898056444678 megatons of tnt = 68.8507642644 (7-B)

I don't like this calculation personally because the more directly cleancut width of the turbolaser within the actual original scan gives it a much narrower radius and perhaps the water and angle distorts the size of how big the beam looks in this scan.