Board Thread:Support Requests - Getting Technical/@comment-93604-20171120230817/@comment-9605025-20180130171646

reply to #49 Okay, I see where you were going with  now. - reply to #50 I don't think  will ever execute. the reason being that whitespace is stripped from the parser function parameters. Therefore, you are testing to see if the third parameter is empty. Whitespace is not the same as empty. In the event the the third parameter is not specified, the interpreter uses literally ; thus, also not an empty string.

Test Case:
 * Edit:


 * Okay, so, I was wrong about  never being used. Apparently, if you specify the parameter but just leave it empty that will work. However, leaving it unspecified will evaluate to  . This is in contrast to   which will evaluate to   both when unspecified and when left empty.