Thread:ByAsura/@comment-25295648-20200806192204/@comment-25295648-20200814124428

Repaste the stuff with better formatting:

Note: This is ByAsura. Fan has been blocked, so I'm editing this blog on his wishes. These are all direct quotes.

I think finding the size of the explosion based on the planetary curvature wrong because that would imply these star destroyers are hundreds of kilometers in width or magically, midway through, the turbolasers broadened out again despite it being obvious they were thinning down. Obviously these beams weren't dozens to hundreds of kilometers, this isn't a Deathstar laser lol.

Even the highest clouds are only 76-85 kilometers

https://en.wikipedia.org/wiki/Noctilucent_cloud

If this really is thousands of kilometers in blast radius, the height would far exceed 76-85 kilometers and be far above the clouds, when they clearly aren't in the scan.

The angle could simply be distorting the curvature, or it's just artist error not realizing how wonky and out of scale the horizon would be if drawing it curved.

The angle and scale of the beams are all the same. So we can directly scale the ISD to the explosion:


 * Star Destroyer Width = 148 pixels = 600 meters
 * Explosion Diameter = 364 pixels = 1475.67567568 meters
 * Explosion Radius = 737.83783784 meters = 1.71029773 square km

Using Nukemap, I get:


 * Fireball radius = 265 kilotons of tnt
 * Heavy blast damage radius = 39 kilotons of tnt

Divide by 3:


 * Fireball radius = 88.333 kilotons of tnt (7-C)
 * Heavy blast damage radius = 13 kilotons of tnt (7-C)

Conversely, if we took the diameter of the beams and assume it vaporized to the sea floor, we could get another viable energy number:


 * Star Destroyer Width = 148 pixels = 600 meters
 * Beam width in second part of the panel = 4 pixels = 16.2162162 meters

https://oceanservice.noaa.gov/facts/oceandepth.html#:~:text=The%20average%20ocean%20depth%20is%202.3%20miles%20.&text=The%20deepest%20part%20of%20the,U.S.%20territorial%20island%20of%20Guam

Sea Floor is on average 2.3 miles down from the surface

https://www.omnicalculator.com/math/cylinder-volume

That gives a volume of 764479 cubic meters

Density of seawater is 1023.6 kg/m^3

1023.6 kg/m^3 * 764479 cubic meters = 782,520,704 kilograms

http://scienceline.ucsb.edu/getkey.php?key=3887#:~:text=Heat%20capacity%20is%20the%20amount,3.993%20J%2F(g%20K).

Seawater has a heat capacity of 3.993 joules per gram

Blasters are able to melt metal, which assuming Titanium, I get 1668°C.

https://www.windows2universe.org/earth/Water/temp.html#:~:text=Ocean%20water%2C%20with%20an%20average,Celsius%20(62.6%20degrees%20Fahrenheit).

Average temperature of water is 17°C

That is a temperature change of 1651°C

https://www.omnicalculator.com/physics/specific-heat

= 1.2329644209942332 megatons of tnt

https://www.britannica.com/science/seawater/Thermal-properties#:~:text=Evaporation%20below%20100%20%C2%B0C,heat%20of%20vaporization%20is%20liberated. https://www.windows2universe.org/earth/Water/temp.html#:~:text=Ocean%20water%2C%20with%20an%20average,Celsius%20(62.6%20degrees%20Fahrenheit).

Latent heat of vaporization is 540 calories per gram

782,520,704 kilograms * 540 calories per gram = 422.56118 kilotons of tnt

1.2329644209942332 megatons of tnt + 422.56118 kilotons of tnt = 1.6555256 megatons of tnt (Low 7-B)