User:KingTempest16/Sandbox1

= One Piece Calcs = Calcing these offsite, because every time a calc of mine is even sandboxed on VSBW, the entire world knows about it before I can even finish it.

Whitebeard's Kabutowari
Welp, calcing this again.

The issue is that now, we're given better logic behind a specific feat.

Introduction
Whitebeard slams Vice Admiral Ronse's head down so hard that someone in a distant island can feel it, and the island itself shakes. That is found in Chapter 556.

The issue is that that specific person was ignorant of the reasons of the earthquakes, while the Paramount War was a worldwide issue.

We're informed it's a worldwide issue because we see that everybody in the world knows about the fight. People in the South Blue, East Blue, North Blue, West Blue, and Grand Line knew about it. Even Momonga said that the whole world could sense it. What is the one place that wasn't shown? The Calm Belt.

The Calm Belt is located right next to Marineford and Marijoa, and it's a place in the world that doesn't receive news. If literally everywhere else in the world receives news, and this place doesn't, it means that this is the only place that doesn't receive the news, which means that island is in the Calm Belt.

The thing about the Calm Belt is that it's a global landmark. If we see the entire planet, we can see the calm belt. It's not something that's a dot on the map like the other big islands. So what I will do is use this information, but instead of me calcing it compared to the planet (since we... can't see it compared to the planet, we don't ever get that), I'll use a different picture to calculate something that can be compared to the Calm Belt, the Grand Line.

Explanation
We get this map on Chapter 522. It's a map that's closer to the screen than any other, things are clear and we can clearly see the distance between the landmarks. We see the Grand Line, Marineford, and the Calm Belt's Distance. We see that Marineford is directly in front of Marijoa, which is shown to be in the center/middle of the Grand Line by the world map shown here. We can use an island on the grand line, Alabasta, which has a calculated short side here (we don't know if the long side stretches to the calm belt or anything, would be better to use the small size) to use as the diameter of the Grand Line.

Size of the Grand Line
https://vsbattles.fandom.com/wiki/User_blog:CinCameron20/Energy_required_for_destroying_Dressrosa_and_Alabasta

Black = 2.5 px = 50 km

Red = 159 px = 3,180 km for the length

Grand Line Width: 28.2 px = 3,180 km

Distance from Marineford to the Calm Belt
Like I said before, Marijoa, and in extension, Marineford, is smack dab in the middle of the Grand Line. So to find the border, what do I do?

3,180/2 = 1,590 km

Calculating the Yield of the Earthquake
https://vsbattles.fandom.com/wiki/Earthquake_Calculations

The Island was clearly shaking. Like... we see the island itself have lines of movement. We don't see any major damage, but we see many are frightened, and people notice it outdoors. Not enough for 7 but seems a little more than 5. Intensity 6 is what I'll use, which will give me Magnitude 5 at a distance.

r ≥ 700 km: In this case the formula is (Magnitude at distance) + 6.399 + 1.66 * log10((r/110) * ((2 * π)/360)) = Richter Magnitude of Earthquake

5 + 6.399 + 1.66 * log10(([3,180/2]/110) * ((2 * π)/360)) = 10.4061237992

Plugging that in here

5.014016e+24 Joules = 1198.3785850860419941 Teratons = 1.1983785850860419941 Petatons (Continent level)

Whitebeard's Kaishin
Yes, I've calced this a handful of times, and I didn't wanna do it again.

But I was informed of a method that could be used that ignores Marineford's size and all, and it doesn't require pixel scaling to the Marineford building.

Source. Thank you again The_Calaca

I found a better way to find the height of Whitebeard's first tsunami, since the images used have a very curved angle due to the plane in which they are found.

''The idea is simple. I'm going to use the ship that falls from the sky where Luffy and company come, the one that was stranded on the top of the frozen tsunami.''



Thousand Sunny: 106.8px = 56m.

Battleship Lined Portion: 120.8px = 63.34m



Battleship Lined Portion: 9px.

Battleship Length: 66px = 464.49m.

Screen Height: 1199 px.

Battleship: 53.7 px = 422.26 m.

2atan(tan(70deg/2) * [53.7/1199]) = 3.59246214 degrees

6732.4 meters away from the screen

1.5667 x Log(6732.4) + 7.0781 + (-4.9 + 4.7)/1.5 = 12.9423604667

http://www.convertalot.com/earthquake_power__calculator.html

1.635086e+24 Joules = 390.7949 Teratons

Whitebeard's Shima Yurashi
Battleship Lined Portion: 9px = 63.34m.

Battleship Height: 60px = 422.27m.

Battleship Height: 9.9px.

Tsunami: 122px = 5203.758m

1.5667 * Log(5203.758) + 7.0781 + (-4.9 + 4.7)/1.5 = 12.767120654.

http://www.convertalot.com/earthquake_power__calculator.html

8.926495e+23 Joules = 213.348 Teratons

Kaidou's Flame Clouds
The Numbers can casually walk through the gates on the roof, and the Numbers are stated to be as tall as Oars, 67 Meters, supported with Hatcha being 66.8 Meters via vivre card.

Roof Gate: 67 m = 45 px

Hill Height: 313 px = 466.02222222222 m

Hill Height: 466.02222222222 m = 5 px

Eye Length: 49.2 px = 4585.6586666666 m

Eye Length: 4585.6586666666 m = 41.1 px

Onigashima Diameter: 726.2 px = 81024.460431467 m

Onigashima Diameter: 81024.460431467 m = 36 px

Onigashima Height from Ground: 259 px = 582925.97921528 m

Work in progress

Luffy's Dimensions
Luffy: 1.72 m = 244 + 191.7 + 196.5 + 3 = 635.2 px

Straw Hat: 97 px = 0.26265743073048 m

Shoulder Length: 108 px = 0.29244332493703 m

Head to Chin: 67 px = 0.18142317380353 m

Thumb Length
Straw Hat: 0.26265743073048 m = 132.5 px

Paw to Face: 50.2 px = 0.099512475642763 m

Thumb Length: 79.1 px = 0.15680153034547 m

Size of Kuma's Hand / Surface Area
https://bikehike.org/how-long-is-the-average-thumb/

2.54 cm is the length of average thumb

https://www.ncbi.nlm.nih.gov/pmc/articles/PMC2938623/#:~:text=The%20mean%20palm%20area%20in,0.001)%20%5BTable%202%5D.

146.50 cm2 is the mean area of average adult male hand

(0.15680153034547 / 0.0254)^2 * 146.50 = 5583.04059162 cm2 = 0.558304059162 m2

0.558304059162 m2 * 0.099512475642763 m = 0.0555582191 m3

Mass of Air between em
Density of air = 1.225 kg/m3

1.225 * 0.0555582191 = 0.06805881839 kg

Luffy's mass
(1.72 / 1.708)^3 * 62.5 = 63.8266071332 kg

Luffy's Surface area
(pi/4) * 0.18142317380353 * 0.29244332493703 = 0.04167008194

Initial Velocity
51625037.6921 = 63.8266071332v

51625037.6921 / 63.8266071332 = v

v = 808832.554492 m/s

Units
u = 808832.554492 m/s OR 343 m/s

t = 259200 s

m = 63.8266071332 kg

p = 1.225 kg/m3

C = 0.04

A = 0.04167008194

Formula
u t - ((1/2) {(1/2) (1/m) ρ C A [(1/u) + (1/2) (1/m) ρ C A t]^-2}) * t^2

808832.554492 * 259200 - ((1/2) {(1/2) (1/63.8266071332) 1.225 * 0.04 * 0.04167008194 * [(1/808832.554492) + (1/2) (1/63.8266071332) 1.225 * 0.04 * 0.04167008194 * 259200]^-2}) * 259200^2 = 209649366864.895616018 meters

343 * 259200 - ((1/2) {(1/2) (1/63.8266071332) 1.225 * 0.04 * 0.04167008194 * [(1/343) + (1/2) (1/63.8266071332) 1.225 * 0.04 * 0.04167008194 * 259200]^-2}) * 259200^2 = 88874384.467870580 meters

Calced Speed
Sabaody to Amazon Lily: 209649366864.895616018 m = 610.1 px

Mid Marineford to Calm Belt: 229 px = 78691534194.492 m

This is half. Full width would be 157383068388.984 m

Mach 1 Speed
Sabaody to Amazon Lily: 88874384.467870580 m = 610.1 px

Mid Marineford to Calm Belt: 229 px = 33358849.439669 m

This is half. Full width would be 66717698.879338 m

Calced Speed
Grand Line Diameter: 157383068388.984 m = 26.4 px

One Piece World Diameter: 245 px = 1460562566488.6 meters = 1460562566.4886 kilometers

Mach 1 Speed
Grand Line Diameter: 66717698.879338 m = 26.4 px

One Piece World Diameter: 245 px = 619160463.08477 meters = 619160.46308477 kilometers

Speed of Zunesha
African Elephants can walk at 4.5 mph from what I've searched

According to this article

https://www.ncbi.nlm.nih.gov/pmc/articles/PMC4154292/

Wading through water expends the same energy walking at 0.3 m/s as walking on land at 1.5 m/s. Therefore, wading through water slows you down by 1/5th your normal speed.

Zunesha is 20,000 m wide compared to the dimensions of an african elephant below

https://www.dimensions.com/element/african-elephant

(20,000/4) * 4.5/5 = 4500 mph = 2011.68 m/s

Timeframe of Zunesha moving
To find out how long Zunesha has walked in the grand line recently since the strawhats first arrived, since they didn't go through a large portion of the world in the span of a week+ of the SHs being there, and they couldn't risk leaving the grand line (meaning Zunesha was still in the grand line), I set up this imgur link explaining the timeframe since they first arrived. It's been 35 days.

35 days = 3.024e6 s

Distance Zunesha Moved
2011.68 * 3.024e6 = 6083320320 meters

This would be less than half of the circumference of the earth

Full Circumference of the earth
Full circumference assuming half, since Zunesha stayed in the new world the entire time = 12166640640

Diameter of earth = 3872762000 meters = 3,872,762 km

Mass, Gravity, and Binding Energy
Since the planet is an irl Earth-like planet (i.e. very rocky), the density must be higher than the density of water, and very likely the same density of irl Earth. To account for the ambiguity both ends will be included.

Density of water = 1000 kg/m^3

Density of Earth = 5514 kg/m^3

Mass via water density = (4/3) * pi * (3872762000/2)^3 * 1000 = 3.04131e31 kg

Mass via Earth density = (4/3) * pi * (3872762000/2)^3 * 5514 = 1.67698e32 kg

Surface gravity via water density = 6.674e-11 * 3.04131e31 / (3872762000/2)^2 = 541.334 m/s^2

Surface gravity via Earth density = 6.674e-11 * 1.67698e32 / (3872762000/2)^2 = 2984.92 m/s^2

GBE via water density = (3/5) * 6.674e-11 * (3.04131e31)^2 / (3872762000/2) = 1.9128e43 J

GBE via Earth density = (3/5) * 6.674e-11 * (1.67698e32)^2 / (3872762000/2) = 5.8157e44 J